x^2-10x+16=(x-8)

Solution for x^2-10x+16=(x-8) equation:

x^2-10x+16=(x-8)

We move all terms to the left:

x^2-10x+16-((x-8))=0


We calculate terms in parentheses: -((x-8)), so:

(x-8)

We get rid of parentheses

x-8

Back to the equation:

-(x-8)


We get rid of parentheses

x^2-10x-x+8+16=0

We add all the numbers together, and all the variables

x^2-11x+24=0

a = 1; b = -11; c = +24;
Δ = b2-4ac
Δ = -112-4·1·24
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-5}{2*1}=\frac{6}{2}
=3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+5}{2*1}=\frac{16}{2}
=8
$